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Australian Open: Raonic beat former champion Wawrinka

16th-seeded Raonic beat 2014 champion Wawrinka in Australian Open’s 2nd round after 4-hour battle of tiebreaks

  | 17.01.2019
Australian Open: Raonic beat former champion Wawrinka Milos Raonic of Canada in action against Stan Wawrinka (not seen) of Switzerland during Australian Open 2019 Men's Singles match in Melbourne, Australia on January 17, 2019. Raonic won the match with 3-1. ( Recep Şakar - Anadolu Agency )

By Fatih Erel

ISTANBUL 

Canadian Milos Raonic reached round three of the Australian Open on Thursday with his victory against former champion Stan Wawrinka.

The 16th-seeded Raonic beat 2014 champion Wawrinka 6-7 (4), 7-6 (6), 7-6 (11), 7-6 (5) in the Australian Open’s second round in four sets after a four-hour battle of tiebreaks.

The 11th-seeded Croatian Borna Coric, 12th-seeded Italian Fabio Fognini and 23rd-seeded Spanish Pablo Carreno Busta also reached the third round.

The 4th-seeded Japanese Naomi Osaka defeated Slovenian Tamara Zidansek to reach the third round, while 6th-seeded Ukranian Elina Svitolina beat Slovak Viktoria Kuzmova and 7th-seeded Czech Karolina Pliskova defeated the U.S.'s Madison Brengle in round two.

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